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-4=-16.1t^2+40t
We move all terms to the left:
-4-(-16.1t^2+40t)=0
We get rid of parentheses
16.1t^2-40t-4=0
a = 16.1; b = -40; c = -4;
Δ = b2-4ac
Δ = -402-4·16.1·(-4)
Δ = 1857.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-\sqrt{1857.6}}{2*16.1}=\frac{40-\sqrt{1857.6}}{32.2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+\sqrt{1857.6}}{2*16.1}=\frac{40+\sqrt{1857.6}}{32.2} $
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